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8m^2+14m-9=0
a = 8; b = 14; c = -9;
Δ = b2-4ac
Δ = 142-4·8·(-9)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-22}{2*8}=\frac{-36}{16} =-2+1/4 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+22}{2*8}=\frac{8}{16} =1/2 $
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