8m2+3=13

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Solution for 8m2+3=13 equation:



8m^2+3=13
We move all terms to the left:
8m^2+3-(13)=0
We add all the numbers together, and all the variables
8m^2-10=0
a = 8; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·8·(-10)
Δ = 320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{320}=\sqrt{64*5}=\sqrt{64}*\sqrt{5}=8\sqrt{5}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{5}}{2*8}=\frac{0-8\sqrt{5}}{16} =-\frac{8\sqrt{5}}{16} =-\frac{\sqrt{5}}{2} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{5}}{2*8}=\frac{0+8\sqrt{5}}{16} =\frac{8\sqrt{5}}{16} =\frac{\sqrt{5}}{2} $

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