8m2+64m=0

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Solution for 8m2+64m=0 equation: 



8m^2+64m=0

a = 8; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·8·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*8}=\frac{-128}{16}
=-8
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*8}=\frac{0}{16}
=0
$

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