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8m^2-24=3m
We move all terms to the left:
8m^2-24-(3m)=0
a = 8; b = -3; c = -24;
Δ = b2-4ac
Δ = -32-4·8·(-24)
Δ = 777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{777}}{2*8}=\frac{3-\sqrt{777}}{16} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{777}}{2*8}=\frac{3+\sqrt{777}}{16} $
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