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8n(-3n+7)=13
We move all terms to the left:
8n(-3n+7)-(13)=0
We multiply parentheses
-24n^2+56n-13=0
a = -24; b = 56; c = -13;
Δ = b2-4ac
Δ = 562-4·(-24)·(-13)
Δ = 1888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1888}=\sqrt{16*118}=\sqrt{16}*\sqrt{118}=4\sqrt{118}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{118}}{2*-24}=\frac{-56-4\sqrt{118}}{-48} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{118}}{2*-24}=\frac{-56+4\sqrt{118}}{-48} $
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