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8n(5n+4=2)
We move all terms to the left:
8n(5n+4-(2))=0
We add all the numbers together, and all the variables
8n(5n+2)=0
We multiply parentheses
40n^2+16n=0
a = 40; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·40·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:n_{1}=\frac{-b-\sqrt{\Delta}}{2a}n_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{256}=16n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*40}=\frac{-32}{80} =-2/5n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*40}=\frac{0}{80} =0
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