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8n(8n-6)=0
We multiply parentheses
64n^2-48n=0
a = 64; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·64·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*64}=\frac{0}{128} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*64}=\frac{96}{128} =3/4 $
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