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8n(n+1)=0
We multiply parentheses
8n^2+8n=0
a = 8; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·8·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*8}=\frac{-16}{16} =-1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*8}=\frac{0}{16} =0 $
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