8n+4(1-4n)=-6(n-3)

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Solution for 8n+4(1-4n)=-6(n-3) equation: 



8n+4(1-4n)=-6(n-3)

We move all terms to the left:

8n+4(1-4n)-(-6(n-3))=0

We add all the numbers together, and all the variables

8n+4(-4n+1)-(-6(n-3))=0

We multiply parentheses

8n-16n-(-6(n-3))+4=0



We calculate terms in parentheses: -(-6(n-3)), so:

-6(n-3)

We multiply parentheses

-6n+18

Back to the equation:

-(-6n+18)



We add all the numbers together, and all the variables

-8n-(-6n+18)+4=0

We get rid of parentheses

-8n+6n-18+4=0

We add all the numbers together, and all the variables

-2n-14=0

We move all terms containing n to the left, all other terms to the right

-2n=14

n=14/-2

n=-7

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