8n-3(n-1)=4(n+2)

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Solution for 8n-3(n-1)=4(n+2) equation: 



8n-3(n-1)=4(n+2)

We move all terms to the left:

8n-3(n-1)-(4(n+2))=0

We multiply parentheses

8n-3n-(4(n+2))+3=0



We calculate terms in parentheses: -(4(n+2)), so:

4(n+2)

We multiply parentheses

4n+8

Back to the equation:

-(4n+8)



We add all the numbers together, and all the variables

5n-(4n+8)+3=0

We get rid of parentheses

5n-4n-8+3=0

We add all the numbers together, and all the variables

n-5=0

We move all terms containing n to the left, all other terms to the right

n=5

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