8n2+80n=2n2

Solution for 8n2+80n=2n2 equation:

8n^2+80n=2n^2

We move all terms to the left:

8n^2+80n-(2n^2)=0

determiningTheFunctionDomain
8n^2-2n^2+80n=0

We add all the numbers together, and all the variables

6n^2+80n=0

a = 6; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·6·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*6}=\frac{-160}{12}
=-13+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*6}=\frac{0}{12}
=0
$