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8n^2-47n-6=0
a = 8; b = -47; c = -6;
Δ = b2-4ac
Δ = -472-4·8·(-6)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-49}{2*8}=\frac{-2}{16} =-1/8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+49}{2*8}=\frac{96}{16} =6 $
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