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8n^2-6=306
We move all terms to the left:
8n^2-6-(306)=0
We add all the numbers together, and all the variables
8n^2-312=0
a = 8; b = 0; c = -312;
Δ = b2-4ac
Δ = 02-4·8·(-312)
Δ = 9984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9984}=\sqrt{256*39}=\sqrt{256}*\sqrt{39}=16\sqrt{39}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{39}}{2*8}=\frac{0-16\sqrt{39}}{16} =-\frac{16\sqrt{39}}{16} =-\sqrt{39} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{39}}{2*8}=\frac{0+16\sqrt{39}}{16} =\frac{16\sqrt{39}}{16} =\sqrt{39} $
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