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8n^2=-26n
We move all terms to the left:
8n^2-(-26n)=0
We get rid of parentheses
8n^2+26n=0
a = 8; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·8·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*8}=\frac{-52}{16} =-3+1/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*8}=\frac{0}{16} =0 $
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