8p2-18p+9=0

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Solution for 8p2-18p+9=0 equation:



8p^2-18p+9=0
a = 8; b = -18; c = +9;
Δ = b2-4ac
Δ = -182-4·8·9
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6}{2*8}=\frac{12}{16} =3/4 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6}{2*8}=\frac{24}{16} =1+1/2 $

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