8q+12=2(3q-2)

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Solution for 8q+12=2(3q-2) equation: 



8q+12=2(3q-2)

We move all terms to the left:

8q+12-(2(3q-2))=0



We calculate terms in parentheses: -(2(3q-2)), so:

2(3q-2)

We multiply parentheses

6q-4

Back to the equation:

-(6q-4)



We get rid of parentheses

8q-6q+4+12=0

We add all the numbers together, and all the variables

2q+16=0

We move all terms containing q to the left, all other terms to the right

2q=-16

q=-16/2

q=-8

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