8q+12=4(3-3q)

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Solution for 8q+12=4(3-3q) equation: 



8q+12=4(3-3q)

We move all terms to the left:

8q+12-(4(3-3q))=0

We add all the numbers together, and all the variables

8q-(4(-3q+3))+12=0



We calculate terms in parentheses: -(4(-3q+3)), so:

4(-3q+3)

We multiply parentheses

-12q+12

Back to the equation:

-(-12q+12)



We get rid of parentheses

8q+12q-12+12=0

We add all the numbers together, and all the variables

20q=0

q=0/20

q=0

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