8r-4(r+2)=3(2r-4)-6

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Solution for 8r-4(r+2)=3(2r-4)-6 equation: 



8r-4(r+2)=3(2r-4)-6

We move all terms to the left:

8r-4(r+2)-(3(2r-4)-6)=0

We multiply parentheses

8r-4r-(3(2r-4)-6)-8=0



We calculate terms in parentheses: -(3(2r-4)-6), so:

3(2r-4)-6

We multiply parentheses

6r-12-6

We add all the numbers together, and all the variables

6r-18

Back to the equation:

-(6r-18)



We add all the numbers together, and all the variables

4r-(6r-18)-8=0

We get rid of parentheses

4r-6r+18-8=0

We add all the numbers together, and all the variables

-2r+10=0

We move all terms containing r to the left, all other terms to the right

-2r=-10

r=-10/-2

r=+5

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