8r-4(r+2)=3(3r-4)-11

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Solution for 8r-4(r+2)=3(3r-4)-11 equation: 



8r-4(r+2)=3(3r-4)-11

We move all terms to the left:

8r-4(r+2)-(3(3r-4)-11)=0

We multiply parentheses

8r-4r-(3(3r-4)-11)-8=0



We calculate terms in parentheses: -(3(3r-4)-11), so:

3(3r-4)-11

We multiply parentheses

9r-12-11

We add all the numbers together, and all the variables

9r-23

Back to the equation:

-(9r-23)



We add all the numbers together, and all the variables

4r-(9r-23)-8=0

We get rid of parentheses

4r-9r+23-8=0

We add all the numbers together, and all the variables

-5r+15=0

We move all terms containing r to the left, all other terms to the right

-5r=-15

r=-15/-5

r=+3

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