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8r^2-17=2471
We move all terms to the left:
8r^2-17-(2471)=0
We add all the numbers together, and all the variables
8r^2-2488=0
a = 8; b = 0; c = -2488;
Δ = b2-4ac
Δ = 02-4·8·(-2488)
Δ = 79616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{79616}=\sqrt{256*311}=\sqrt{256}*\sqrt{311}=16\sqrt{311}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{311}}{2*8}=\frac{0-16\sqrt{311}}{16} =-\frac{16\sqrt{311}}{16} =-\sqrt{311} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{311}}{2*8}=\frac{0+16\sqrt{311}}{16} =\frac{16\sqrt{311}}{16} =\sqrt{311} $
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