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8r^2-6=194
We move all terms to the left:
8r^2-6-(194)=0
We add all the numbers together, and all the variables
8r^2-200=0
a = 8; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·8·(-200)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*8}=\frac{-80}{16} =-5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*8}=\frac{80}{16} =5 $
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