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8r^2-8r+10=8
We move all terms to the left:
8r^2-8r+10-(8)=0
We add all the numbers together, and all the variables
8r^2-8r+2=0
a = 8; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·8·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$r=\frac{-b}{2a}=\frac{8}{16}=1/2$
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