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8s(s+3)=72
We move all terms to the left:
8s(s+3)-(72)=0
We multiply parentheses
8s^2+24s-72=0
a = 8; b = 24; c = -72;
Δ = b2-4ac
Δ = 242-4·8·(-72)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24\sqrt{5}}{2*8}=\frac{-24-24\sqrt{5}}{16} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24\sqrt{5}}{2*8}=\frac{-24+24\sqrt{5}}{16} $
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