8t-(16t2+1)=0

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Solution for 8t-(16t2+1)=0 equation: 



8t-(16t^2+1)=0

We get rid of parentheses

-16t^2+8t-1=0

a = -16; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·(-16)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-8}{-32}=1/4$

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