8t=-(16t2+1)

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Solution for 8t=-(16t2+1) equation: 



8t=-(16t^2+1)

We move all terms to the left:

8t-(-(16t^2+1))=0



We calculate terms in parentheses: -(-(16t^2+1)), so:

-(16t^2+1)

We get rid of parentheses

-16t^2-1

Back to the equation:

-(-16t^2-1)



We get rid of parentheses

16t^2+8t+1=0

a = 16; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{-8}{32}=-1/4$

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