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8u(6u-5)=0
We multiply parentheses
48u^2-40u=0
a = 48; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·48·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*48}=\frac{0}{96} =0 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*48}=\frac{80}{96} =5/6 $
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