8u(u+4)=0

Solution for 8u(u+4)=0 equation:

8u(u+4)=0

We multiply parentheses

8u^2+32u=0

a = 8; b = 32; c = 0;
Δ = b2-4ac
Δ = 322-4·8·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-32}{2*8}=\frac{-64}{16}
=-4
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+32}{2*8}=\frac{0}{16}
=0
$