8u+3-3(-3u-1)=3(u-2)

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Solution for 8u+3-3(-3u-1)=3(u-2) equation: 



8u+3-3(-3u-1)=3(u-2)

We move all terms to the left:

8u+3-3(-3u-1)-(3(u-2))=0

We multiply parentheses

8u+9u-(3(u-2))+3+3=0



We calculate terms in parentheses: -(3(u-2)), so:

3(u-2)

We multiply parentheses

3u-6

Back to the equation:

-(3u-6)



We add all the numbers together, and all the variables

17u-(3u-6)+6=0

We get rid of parentheses

17u-3u+6+6=0

We add all the numbers together, and all the variables

14u+12=0

We move all terms containing u to the left, all other terms to the right

14u=-12

u=-12/14

u=-6/7

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