8u+3-3(-3u-1)=3(u-2)

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Solution for 8u+3-3(-3u-1)=3(u-2) equation:



8u+3-3(-3u-1)=3(u-2)
We move all terms to the left:
8u+3-3(-3u-1)-(3(u-2))=0
We multiply parentheses
8u+9u-(3(u-2))+3+3=0
We calculate terms in parentheses: -(3(u-2)), so:
3(u-2)
We multiply parentheses
3u-6
Back to the equation:
-(3u-6)
We add all the numbers together, and all the variables
17u-(3u-6)+6=0
We get rid of parentheses
17u-3u+6+6=0
We add all the numbers together, and all the variables
14u+12=0
We move all terms containing u to the left, all other terms to the right
14u=-12
u=-12/14
u=-6/7

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