8u+38=2(u+1)

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Solution for 8u+38=2(u+1) equation: 



8u+38=2(u+1)

We move all terms to the left:

8u+38-(2(u+1))=0



We calculate terms in parentheses: -(2(u+1)), so:

2(u+1)

We multiply parentheses

2u+2

Back to the equation:

-(2u+2)



We get rid of parentheses

8u-2u-2+38=0

We add all the numbers together, and all the variables

6u+36=0

We move all terms containing u to the left, all other terms to the right

6u=-36

u=-36/6

u=-6

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