8u+40=2(u-1)

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Solution for 8u+40=2(u-1) equation: 



8u+40=2(u-1)

We move all terms to the left:

8u+40-(2(u-1))=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We get rid of parentheses

8u-2u+2+40=0

We add all the numbers together, and all the variables

6u+42=0

We move all terms containing u to the left, all other terms to the right

6u=-42

u=-42/6

u=-7

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