8u-12=2(3u-6)+2u

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Solution for 8u-12=2(3u-6)+2u equation: 



8u-12=2(3u-6)+2u

We move all terms to the left:

8u-12-(2(3u-6)+2u)=0



We calculate terms in parentheses: -(2(3u-6)+2u), so:

2(3u-6)+2u

We add all the numbers together, and all the variables

2u+2(3u-6)

We multiply parentheses

2u+6u-12

We add all the numbers together, and all the variables

8u-12

Back to the equation:

-(8u-12)



We get rid of parentheses

8u-8u+12-12=0

We add all the numbers together, and all the variables

=0

u=0/1

u=0

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