8u-6+2(2u+2)=-6(u+1)

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Solution for 8u-6+2(2u+2)=-6(u+1) equation: 



8u-6+2(2u+2)=-6(u+1)

We move all terms to the left:

8u-6+2(2u+2)-(-6(u+1))=0

We multiply parentheses

8u+4u-(-6(u+1))+4-6=0



We calculate terms in parentheses: -(-6(u+1)), so:

-6(u+1)

We multiply parentheses

-6u-6

Back to the equation:

-(-6u-6)



We add all the numbers together, and all the variables

12u-(-6u-6)-2=0

We get rid of parentheses

12u+6u+6-2=0

We add all the numbers together, and all the variables

18u+4=0

We move all terms containing u to the left, all other terms to the right

18u=-4

u=-4/18

u=-2/9

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