8v+12=6(v-1)

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Solution for 8v+12=6(v-1) equation: 



8v+12=6(v-1)

We move all terms to the left:

8v+12-(6(v-1))=0



We calculate terms in parentheses: -(6(v-1)), so:

6(v-1)

We multiply parentheses

6v-6

Back to the equation:

-(6v-6)



We get rid of parentheses

8v-6v+6+12=0

We add all the numbers together, and all the variables

2v+18=0

We move all terms containing v to the left, all other terms to the right

2v=-18

v=-18/2

v=-9

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