8v+2(v+4)=28

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Solution for 8v+2(v+4)=28 equation: 



8v+2(v+4)=28

We move all terms to the left:

8v+2(v+4)-(28)=0

We multiply parentheses

8v+2v+8-28=0

We add all the numbers together, and all the variables

10v-20=0

We move all terms containing v to the left, all other terms to the right

10v=20

v=20/10

v=2

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