8v+2-2(-2v-3)=6(v-1)

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Solution for 8v+2-2(-2v-3)=6(v-1) equation: 



8v+2-2(-2v-3)=6(v-1)

We move all terms to the left:

8v+2-2(-2v-3)-(6(v-1))=0

We multiply parentheses

8v+4v-(6(v-1))+6+2=0



We calculate terms in parentheses: -(6(v-1)), so:

6(v-1)

We multiply parentheses

6v-6

Back to the equation:

-(6v-6)



We add all the numbers together, and all the variables

12v-(6v-6)+8=0

We get rid of parentheses

12v-6v+6+8=0

We add all the numbers together, and all the variables

6v+14=0

We move all terms containing v to the left, all other terms to the right

6v=-14

v=-14/6

v=-2+1/3

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