8v+2-2(-5v-1)=6(v-1)

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Solution for 8v+2-2(-5v-1)=6(v-1) equation: 



8v+2-2(-5v-1)=6(v-1)

We move all terms to the left:

8v+2-2(-5v-1)-(6(v-1))=0

We multiply parentheses

8v+10v-(6(v-1))+2+2=0



We calculate terms in parentheses: -(6(v-1)), so:

6(v-1)

We multiply parentheses

6v-6

Back to the equation:

-(6v-6)



We add all the numbers together, and all the variables

18v-(6v-6)+4=0

We get rid of parentheses

18v-6v+6+4=0

We add all the numbers together, and all the variables

12v+10=0

We move all terms containing v to the left, all other terms to the right

12v=-10

v=-10/12

v=-5/6

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