8v+5(3+2v)=-40+7v

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Solution for 8v+5(3+2v)=-40+7v equation: 



8v+5(3+2v)=-40+7v

We move all terms to the left:

8v+5(3+2v)-(-40+7v)=0

We add all the numbers together, and all the variables

8v+5(2v+3)-(7v-40)=0

We multiply parentheses

8v+10v-(7v-40)+15=0

We get rid of parentheses

8v+10v-7v+40+15=0

We add all the numbers together, and all the variables

11v+55=0

We move all terms containing v to the left, all other terms to the right

11v=-55

v=-55/11

v=-5

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