8v+5-(-2v-3)=4(v-1)

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Solution for 8v+5-(-2v-3)=4(v-1) equation: 



8v+5-(-2v-3)=4(v-1)

We move all terms to the left:

8v+5-(-2v-3)-(4(v-1))=0

We get rid of parentheses

8v+2v-(4(v-1))+3+5=0



We calculate terms in parentheses: -(4(v-1)), so:

4(v-1)

We multiply parentheses

4v-4

Back to the equation:

-(4v-4)



We add all the numbers together, and all the variables

10v-(4v-4)+8=0

We get rid of parentheses

10v-4v+4+8=0

We add all the numbers together, and all the variables

6v+12=0

We move all terms containing v to the left, all other terms to the right

6v=-12

v=-12/6

v=-2

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