8v+6-2(-2v-3)=2(v-1)

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Solution for 8v+6-2(-2v-3)=2(v-1) equation: 



8v+6-2(-2v-3)=2(v-1)

We move all terms to the left:

8v+6-2(-2v-3)-(2(v-1))=0

We multiply parentheses

8v+4v-(2(v-1))+6+6=0



We calculate terms in parentheses: -(2(v-1)), so:

2(v-1)

We multiply parentheses

2v-2

Back to the equation:

-(2v-2)



We add all the numbers together, and all the variables

12v-(2v-2)+12=0

We get rid of parentheses

12v-2v+2+12=0

We add all the numbers together, and all the variables

10v+14=0

We move all terms containing v to the left, all other terms to the right

10v=-14

v=-14/10

v=-1+2/5

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