8v-2+2(2v+1)=-4(v+1)

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Solution for 8v-2+2(2v+1)=-4(v+1) equation: 



8v-2+2(2v+1)=-4(v+1)

We move all terms to the left:

8v-2+2(2v+1)-(-4(v+1))=0

We multiply parentheses

8v+4v-(-4(v+1))+2-2=0



We calculate terms in parentheses: -(-4(v+1)), so:

-4(v+1)

We multiply parentheses

-4v-4

Back to the equation:

-(-4v-4)



We add all the numbers together, and all the variables

12v-(-4v-4)=0

We get rid of parentheses

12v+4v+4=0

We add all the numbers together, and all the variables

16v+4=0

We move all terms containing v to the left, all other terms to the right

16v=-4

v=-4/16

v=-1/4

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