8v2+36v+29=0

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Solution for 8v2+36v+29=0 equation:



8v^2+36v+29=0
a = 8; b = 36; c = +29;
Δ = b2-4ac
Δ = 362-4·8·29
Δ = 368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{368}=\sqrt{16*23}=\sqrt{16}*\sqrt{23}=4\sqrt{23}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{23}}{2*8}=\frac{-36-4\sqrt{23}}{16} $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{23}}{2*8}=\frac{-36+4\sqrt{23}}{16} $

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