8w2+10w-33=0

Solution for 8w2+10w-33=0 equation:

8w^2+10w-33=0

a = 8; b = 10; c = -33;
Δ = b2-4ac
Δ = 102-4·8·(-33)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-34}{2*8}=\frac{-44}{16}
=-2+3/4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+34}{2*8}=\frac{24}{16}
=1+1/2
$