8x(2x+5)+25=180

Solution for 8x(2x+5)+25=180 equation:

8x(2x+5)+25=180

We move all terms to the left:

8x(2x+5)+25-(180)=0

We add all the numbers together, and all the variables

8x(2x+5)-155=0

We multiply parentheses

16x^2+40x-155=0

a = 16; b = 40; c = -155;
Δ = b2-4ac
Δ = 402-4·16·(-155)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-48\sqrt{5}}{2*16}=\frac{-40-48\sqrt{5}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+48\sqrt{5}}{2*16}=\frac{-40+48\sqrt{5}}{32}
$