8x(2x-12)=60

Solution for 8x(2x-12)=60 equation:

8x(2x-12)=60

We move all terms to the left:

8x(2x-12)-(60)=0

We multiply parentheses

16x^2-96x-60=0

a = 16; b = -96; c = -60;
Δ = b2-4ac
Δ = -962-4·16·(-60)
Δ = 13056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13056}=\sqrt{256*51}=\sqrt{256}*\sqrt{51}=16\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-16\sqrt{51}}{2*16}=\frac{96-16\sqrt{51}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+16\sqrt{51}}{2*16}=\frac{96+16\sqrt{51}}{32}
$