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8x(2x-2)=-32
We move all terms to the left:
8x(2x-2)-(-32)=0
We add all the numbers together, and all the variables
8x(2x-2)+32=0
We multiply parentheses
16x^2-16x+32=0
a = 16; b = -16; c = +32;
Δ = b2-4ac
Δ = -162-4·16·32
Δ = -1792
Delta is less than zero, so there is no solution for the equation
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