8x(3x+1)=912

Solution for 8x(3x+1)=912 equation:

8x(3x+1)=912

We move all terms to the left:

8x(3x+1)-(912)=0

We multiply parentheses

24x^2+8x-912=0

a = 24; b = 8; c = -912;
Δ = b2-4ac
Δ = 82-4·24·(-912)
Δ = 87616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{87616}=296$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-296}{2*24}=\frac{-304}{48}
=-6+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+296}{2*24}=\frac{288}{48}
=6
$