8x(3x+4)=26

Solution for 8x(3x+4)=26 equation:

8x(3x+4)=26

We move all terms to the left:

8x(3x+4)-(26)=0

We multiply parentheses

24x^2+32x-26=0

a = 24; b = 32; c = -26;
Δ = b2-4ac
Δ = 322-4·24·(-26)
Δ = 3520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3520}=\sqrt{64*55}=\sqrt{64}*\sqrt{55}=8\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{55}}{2*24}=\frac{-32-8\sqrt{55}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{55}}{2*24}=\frac{-32+8\sqrt{55}}{48}
$