8x(3x-8)=24

Solution for 8x(3x-8)=24 equation:

8x(3x-8)=24

We move all terms to the left:

8x(3x-8)-(24)=0

We multiply parentheses

24x^2-64x-24=0

a = 24; b = -64; c = -24;
Δ = b2-4ac
Δ = -642-4·24·(-24)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-80}{2*24}=\frac{-16}{48}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+80}{2*24}=\frac{144}{48}
=3
$