8x(6x+6)=10

Solution for 8x(6x+6)=10 equation:

8x(6x+6)=10

We move all terms to the left:

8x(6x+6)-(10)=0

We multiply parentheses

48x^2+48x-10=0

a = 48; b = 48; c = -10;
Δ = b2-4ac
Δ = 482-4·48·(-10)
Δ = 4224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4224}=\sqrt{64*66}=\sqrt{64}*\sqrt{66}=8\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-8\sqrt{66}}{2*48}=\frac{-48-8\sqrt{66}}{96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+8\sqrt{66}}{2*48}=\frac{-48+8\sqrt{66}}{96}
$