8x(x+1)=2(3x-1)

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Solution for 8x(x+1)=2(3x-1) equation: 



8x(x+1)=2(3x-1)

We move all terms to the left:

8x(x+1)-(2(3x-1))=0

We multiply parentheses

8x^2+8x-(2(3x-1))=0



We calculate terms in parentheses: -(2(3x-1)), so:

2(3x-1)

We multiply parentheses

6x-2

Back to the equation:

-(6x-2)



We get rid of parentheses

8x^2+8x-6x+2=0

We add all the numbers together, and all the variables

8x^2+2x+2=0

a = 8; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·8·2
Δ = -60
Delta is less than zero, so there is no solution for the equation

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